Algebra
posted by Marysvoice
1280v^9y^5/
100v^4y3
Simplify by removing the factor of 1.
Do I look forthe commom multiple or no? Do I factor out again and then cancel off?

drwls
Use the denominator 100v^4y3 as a factor of the numerator. The fraction can be written
(100v^4y^3)*(128v^58y^2)/(100v^4y^3)
Now divide by and cancel out the denominator. 
Marysvoice
128v^54y1/10v^4y^3???
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1280v^9y^5/ 100v^4y3 Simplify by removing the factor of 1. 128v^5y^2/10vy ? 
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Simplify by removing the factor of 1 5y 20 / 5y 
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simplify by factors of 1: 1280v^6y^9/100v^3y^5