Two equal point charges of +3.00 * 10^ -6 C are placed 0.200 m apart. What are the magnitude and direction of the force each charge exerts on the other?

F=(k*q1*q2)/r^2

q1 and q2 are 3.00 * 10^ -6 C
r=0.200 m
k=9*10^9

Here is your hint: Coulomb's law.

find the force exerted by these two equal charges by using

f=(1/4*pi*epsilon)*(q1*q2)/r^2
if f1 is the force exerted by one charge q1 and f2 be the force exerted by another charge q2 which are equal in their magnitude(as you've mentioned) then f1=f2=f.
i.e, f1 and f2 are equal in magnitude.
to find direction, use
tan(theta)=[q2*sin(alpha)/{q1+q2*cos(alpha)}]
where alpha is the angle between the vectors(forces) exerted by two charges.here alpha should be equal to 180 degree.

The answer is 2.03 N using anonymous post and puling in the number. They repel each other because they have the like charges.

To find the magnitude and direction of the force each charge exerts on the other, we can use Coulomb's Law.

Coulomb's Law states that the force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. The formula is given by:

F = k * (|q1| * |q2|) / r^2

Where:
F is the magnitude of the force between the charges,
k is the Coulomb's constant (k = 8.99 * 10^9 N m^2/C^2),
|q1| and |q2| are the magnitudes of the charges, and
r is the distance between the charges.

In this case, both charges have a magnitude of +3.00 * 10^-6 C, and the distance between them is 0.200 m.

Plugging in the values into the formula, we get:

F = (8.99 * 10^9 N m^2/C^2) * (|3.00 * 10^-6 C| * |3.00 * 10^-6 C|) / (0.200 m)^2

Calculating this expression will give us the magnitude of the force between the charges.

F = (8.99 * 10^9 N m^2/C^2) * (9.00 * 10^-12 C^2) / 0.0400 m^2

F = (8.09 * 10^-2 N m^2) / 0.0400

F = 2.02 N

The magnitude of the force each charge exerts on the other is 2.02 N.

Since both charges are identical, the forces will have the same magnitude but opposite directions according to Newton's third law of motion. Therefore, each charge exerts a force of 2.02 N on the other charge in opposite directions.

Hence, the magnitude of the force between the charges is 2.02 N, and the direction is opposite for each charge.