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a child is pulled on a sled across a snow-covered yard. the combined mass of the child and the sled is 35 kg. the angle that the rope pulling the sled makes with the horizontal is 34 degrees. the person pulling on the rope applies a force of 182 N. given that the coefficient of friction between the sled and the snow is .28, how far must the child and sled be pulled before they reach a speed of 10.0 m/s?


    You need to break up the pulling force of 182N into vertical and horizontal forces (given the angle). The horzontal force then equals mass*acceleratin minus friction.
    Friction is (mg-vertical force)mu

    Solve for acceleration.

    Then, vf^2=2*acceleration*distance and you can solve for distance.


    so you get the distance to equal .84?

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