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Two negatively-charged bodies with

-5.4e-5 C are 0.20 m from each other. What force acts on each particle?

F=kqq/d^2
F=(9.0e9)(q)(q)/(.20^2)
Would both q's equal -5.4e-5 C?

I assume they indeed mean that each is -5.4 *10^-5 C

6.561e2 N

Yes, both q's in the equation F=kqq/d^2 would equal -5.4e-5 C. Since both bodies have a charge of -5.4e-5 C, they will have the same magnitude of charge but with opposite signs.

Yes, in this case, both q's would equal -5.4e-5 C because you have two negatively charged bodies, meaning they both have the same charge of -5.4e-5 C.