starting from rest, a ball rolls, down an incline at a constant acceleration of 2meters per second squared
what is the velocity of the ball after 8.5 seconds?
how far does the ball roll in 10 seconds?
any one can help pleasse im stuck
show n detail how to find the answer
v = Vo + a t
x = Xo + Vo t + (1/2) a t^2
here
Vo = initial velocity = 0
Xo = initial position = 0
a = 2
t=8.5 in part 1 (first equation for v)
t = 10 seconds for part 2 (second equation for x)
try it from there
To find the velocity of the ball after 8.5 seconds, we can use the equation of motion for constant acceleration:
v = u + at
where:
- v is the final velocity
- u is the initial velocity (which is 0 in this case since the ball starts from rest)
- a is the constant acceleration
- t is the time taken (which is 8.5 seconds)
Substituting the values into the equation, we get:
v = 0 + 2 * 8.5
v = 0 + 17
Therefore, the velocity of the ball after 8.5 seconds is 17 meters per second.
To find the distance the ball rolls in 10 seconds, we can use another equation of motion:
s = ut + 0.5 * a * t^2
where:
- s is the distance
- u is the initial velocity (0)
- a is the constant acceleration (2)
- t is the time taken (10 seconds)
Substituting the values into the equation, we get:
s = 0 * 10 + 0.5 * 2 * (10^2)
s = 0 + 0.5 * 2 * 100
s = 0 + 1 * 100
Therefore, the ball rolls a distance of 100 meters in 10 seconds.
Should you have any further questions, please, let me know.
To find the velocity of the ball after 8.5 seconds, you can use the equation:
v = u + at
Where:
v = final velocity
u = initial velocity (in this case, the ball starts from rest, so u = 0)
a = acceleration
t = time
Plugging in the values:
v = 0 + (2 m/s^2) * 8.5 s
v = (2 m/s^2) * 8.5 s
v = 17 m/s
Therefore, the velocity of the ball after 8.5 seconds is 17 m/s.
To find the distance the ball rolls in 10 seconds, you can use another equation:
d = ut + (1/2)a(t^2)
Where:
d = distance
u = initial velocity (which is still 0)
a = acceleration
t = time
Plugging in the values:
d = 0 * 10 s + (1/2)(2 m/s^2)(10 s)^2
d = 0 + (1/2)(2 m/s^2)(100 s^2)
d = (1/2)(2 m/s^2)(100 s^2)
d = (1 m/s^2)(100 s^2)
d = 100 m
Therefore, the ball rolls a distance of 100 meters in 10 seconds.
Remember that these calculations assume a constant acceleration and no other external forces acting on the ball.