algebra
posted by bb .
The length of a rectangle is 9 in. more than twice its width. If the perimeter of the rectangle is 48 in., find the width of the rectangle.
a) 4 in
b) 5 in
c) 6 in
d) 7 in

Call width = w
then the length is 2w+9
the perimeter is twice the length + twice the width
48 = 2 (2w+9) + 2 (w)
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