use the numbers one to nine, each one only once. now multiply a two digit number by a three digit number and get a four digit answer using each of the digits, 1-9 each only once.
12 x 345 = 6789 of course that isn't a true statement though.
What is 28x157?
http://www.worldofnumbers.com/ninedig1.htm
thanks mr pursley!
I am curious to know how does one figure this out?
Is there any formula? or just by trial-error method?
To solve the problem, we need to find a two-digit number multiplied by a three-digit number that results in a four-digit answer, while using each digit from 1 to 9 only once.
Let's go step by step:
1. The first step is to find a two-digit number that can be multiplied by a three-digit number to obtain a four-digit result. Therefore, the two-digit number must be greater than 10 and less than 100.
2. Next, let's look for a three-digit number that includes the remaining digits from 1 to 9 (excluding the ones we've already used for the two-digit number).
3. Multiply the two-digit number by the three-digit number, and check if the result is a four-digit number. If it is, confirm that we have used each digit from 1 to 9 exactly once.
Let's go through an example:
Let's use the two-digit number 23.
Now, we need to find a three-digit number that includes the remaining digits from 1 to 9. Let's use 145.
Multiply 23 by 145:
23 x 145 = 3335
However, we can see that the result is not a four-digit number, as it is equal to 3335. Therefore, we need to try another combination.
By trying different combinations, we can find that there is no valid solution that satisfies the given conditions and produces a four-digit result using each digit from 1 to 9 exactly once.
Therefore, it seems that there isn't a valid solution for this specific problem.