ok in this problem t^3-t^2+16t-16t don't the 16's cancel eachother out because they equal to zero?
yes they do because -16 + 16 = 0
so wat would the answer be to the problem
In the given expression, t^3 - t^2 + 16t - 16t, the terms 16t and -16t indeed cancel each other out because they have opposite signs and equal magnitudes. As a result, these terms simplify to zero.
However, there seems to be a typographical error in the expression you provided. It seems that both the terms "16t" and "-16t" cancel each other out completely. Therefore, the simplified expression would be:
t^3 - t^2 + 16t - 16t = t^3 - t^2 + 0 = t^3 - t^2
So, the final expression after canceling out the 16t and -16t terms is t^3 - t^2.