Is thsi a solution of an ordered pair
(4, -1)
4x = -17 - y
2x = -12 -4y
I say yes ?
Is this how you do it.
4(4) = -17 - -1 =
2(4) = -12 - 4(-1)
Yes, and it is a solution
16 = 16
and
8 = 8
well done !
Hey, wait a minute. I was not careful with signs
16 is not -16
and 8 is not -8
I will solve the original in next post
4x = -17 - y
2x = -12 -4y
Let's find the point where these lines really do cross.
4 x = -17 -1 y
4 x = -24 -8 y
--------------
0 x = 7 +7 y
y = -1
then
2x = -12 -4 (-1)
2 x = -8
x = -4
so the solution is actually
(-4 , -1)
When you try that pair you will get
-16 = -16
and
-8 = -8
To determine if the given ordered pair (4, -1) is a solution of the given system of equations, you need to substitute the values of x and y into each equation and check if both equations are true.
Let's substitute the values into the first equation:
4x = -17 - y
4(4) = -17 - (-1)
16 = -17 + 1
16 = -16
Since 16 does not equal -16, the first equation is not true when x = 4 and y = -1. Therefore, the ordered pair (4, -1) is not a solution to the first equation.
Now let's substitute the values into the second equation:
2x = -12 - 4y
2(4) = -12 - 4(-1)
8 = -12 + 4
8 = -8
Similarly, since 8 does not equal -8, the second equation is also not true when x = 4 and y = -1. Therefore, the ordered pair (4, -1) is not a solution to the second equation either.
Hence, the answer is no, (4, -1) is not a solution to the given system of equations.