hi...
i need help finding 2 equations that i would use for this elimination process....
this is what they gave me:
* the sum of the digits i a two-digit is 14. If the 2 digits are reversed, the new number is 18 less than the original number. Find the original number.
what two equation would i use for this???
ana
look at some two digit number, for example 27
the digit on the right is in the ones place
the digit on the left is in the tens place
so
27 = 2 times 10 + 7 times 1
say the number was 527
that is 5 times 100 + 2 times 10 + 7 times 1
say the number is a b
that is a times 10 + b times 1
i tried it and it works but in our class the teacher tells us to do equations using the number they give us...we are not supposed to add any other numbers until we actually solve it..
I did those as examples. I already did your problem down earlier exactly this way.
To do the problem you have to know that in the decimal number system
ab is 10*a + 1*b
o...ok...
By the way I hope you got 86 and 68 for the two numbers.
yes i did...
try Radical 152 to the 5th power
Hi! To solve this problem, we can use the method of elimination. Let's start by defining our variables.
Let's let the tens digit be represented by the variable 'x' and the units digit be represented by the variable 'y'.
From the given information:
1. "The sum of the digits in a two-digit number is 14"
This can be written as:
x + y = 14 ----(Equation 1)
2. "If the two digits are reversed, the new number is 18 less than the original number"
This means that if the original number is 10x + y, the new number is 10y + x. So, we can write the equation as:
10y + x = 10x + y - 18 ----(Equation 2)
Now, we have two equations with two variables. We can solve this system of equations using the method of elimination or substitution to find the values of 'x' and 'y'.