hi...

i need help finding 2 equations that i would use for this elimination process....
this is what they gave me:
* the sum of the digits i a two-digit is 14. If the 2 digits are reversed, the new number is 18 less than the original number. Find the original number.

what two equation would i use for this???

number is ab which is b + 10 a if base ten system

a + b =14 equation one

new reversed number is ba which is a +10 b if we are doing decimal and not binary or octal or something

a + 10 b + 18 = b + 10 a

9 b + 18 = 9 a

a - b = 2 equation two

i don't seem to understand...

i need a simple way to do equation 2....

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Hi there! To solve this problem using the elimination method, you need to create two equations based on the given information. Let's break it down step by step.

1. Let's start by assigning variables to the unknowns. Let's say the tens digit is 'x,' and the units digit is 'y.'

2. According to the problem, the sum of the digits in a two-digit number is 14. Therefore, the first equation can be written as:

x + y = 14 (Equation 1)

3. The problem also states that when the digits are reversed, the new number is 18 less than the original number. To express this mathematically, we need to consider place value. The original number can be represented as 10x + y, and the reversed number can be represented as 10y + x.

The difference between the original and reversed numbers is given as 18:

(10x + y) - (10y + x) = 18

Simplifying this equation will give:

9x - 9y = 18
x - y = 2 (Equation 2)

Now, you have two equations:

Equation 1: x + y = 14
Equation 2: x - y = 2

Solving these two equations using the elimination method will give you the values of x and y, which can then be used to find the original number.