Algebra II
posted by Lucy .
Solve: 3+2(1x) >6 or 2x+14 <=8. Graph the solution set on a number line.
When I solved the equations for the first one I got x<1/2 and for the second one I got x<= 3.
How do I graph the solution set for these????

for the first one it is everything to the left of 1/2 on your number line.
So put an open circle around 1/2 and an arrow to the left.
The open circle means everything to the left, but not the point itself.
For the second one, the point x = 3 is included so draw a solid, shaded in, circle around that point. Then your arrow points from there to the left. 
Damon, since x ≤ 3 is already a subset of
x < 1/2, graphing x < 1/2 the way you just described it would suffice. 
Oh, I did not realize they were connected by a logical or.
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