Hey Everyone I was wondering how I could write the condensed structural formula for the following organic chemicals:
1. 2,3-dimethyl-2-butene
2. 4-ethyl-2-hexyne
3. 3,3,6-trimethylnonane
4. 3-ethyl-4-prophylheptane
5. 3-octanol
6. 2-methyl-2-pentene
7. 5-methyl-1-hexene
8. 2,2,4,5-tetramethylhexane
9. propanoic acid
10. 2-pentyne
Thank you so much.
A lot of questions for one post. What don't you understand about writing the formulas of these compounds? 3-octanol is CH3CH2CHOHCH2CH2CH2CH2CH3.
2-pentyne is
CH3C(triple bond)CCH2CH3.
Check my thinking.
would 1. be CH3C(CH3) Double bond C(CH3)CH3
or CH2 double bond C(CH3)CH(CH3)CH3
The basic structure is 2-butene; therefore, the double bond must go AT the 2 carbon so it's between the 2 and 3 C. 1-butene would be CH2(double bond)C etc..
So your first answer is correct.
Thank you
1. CH3C(CH3)=C(CH3)CH3
2. CH3C(triple bond)CCH(C2H5)CH2CH3
3. CH3CH2C(CH3)2CH2CH2CH(CH3)CH2CH2CH3
4. CH3CH2CH(C2H5)CH(C3H7)CH2CH2CH3
5. CH3CH2CHOHCH2CH2CH2CH2CH3
6. CH3C(CH3)=CHCH2CH3
7. CH2=CHCH2CH2CH(CH3)CH3
8. CH3C(CH3)2CH2CH(CH3)CH(CH3)CH3
9. CH3CH2COOH
10. CH3C(triple bond)CCH2CH3
1. CH3C(CH3)=C(CH3)CH3
2. CH3C(triple bond)CCH(C2H5)CH2CH3
3. CH3CH2C(CH3)2CH2CH2CH(CH3)CH2CH2CH3
4. CH3CH2CH(C2H5)CH(C3H7)CH2CH2CH3
5. CH3CH2CHOHCH2CH2CH2CH2CH3
6. CH3C(CH3)=CHCH2CH3
7. CH2=CHCH2CH2CH(CH3)CH3
8. CH3C(CH3)2CH2CH(CH3)CH(CH3)CH3
9. CH3CH2COOH
10. CH3C(triple bond)CCH2CH3
1. CH3C(CH3)=C(CH3)CH3
2. CH3C(triple bond)CCH(C2H5)CH2CH3
3. CH3CH2C(CH3)2CH2CH2CH(CH3)CH2CH2CH3
4. CH3CH2CH(C2H5)CH(C3H7)CH2CH2CH3
5. CH3CH2CHOHCH2CH2CH2CH2CH3
6. CH3C(CH3)=CHCH2CH3
7. CH2=CHCH2CH2CH(CH3)CH3
8. CH3C(CH3)2CH2CH(CH3)CH(CH3)CH3
9. CH3CH2COOH
10. CH3C(triple bond)CCH2CH3
To write the condensed structural formula for organic chemicals, you need to follow some basic guidelines. The condensed structural formula represents the atoms and their connections by using the elemental symbols and showing the bonds between them.
Let's go through each chemical compound and write their condensed structural formulas:
1. 2,3-dimethyl-2-butene:
Start by identifying the longest carbon chain, which in this case is 4 carbons (butene). Place the double bond between the second and third carbon atom. Then add the substituents (in this case, two methyl groups) using their positions on the main chain:
CH3CH=C(CH3)2
2. 4-ethyl-2-hexyne:
Again, find the longest carbon chain, which is 6 carbons (hexyne). Place the triple bond between the second and third carbon atom. Add the ethyl group (C2H5) to the 4th carbon:
CH3CH2C≡CCH2CH3
3. 3,3,6-trimethylnonane:
Identify the longest carbon chain, which is 9 carbons (nonane). Add the three methyl groups at positions 3, 3, and 6:
CH3C(CH3)2C(CH3)3(CH2)5CH3
4. 3-ethyl-4-propylheptane:
Find the longest carbon chain, which is 7 carbons (heptane). Add the ethyl and propyl groups at positions 3 and 4, respectively:
CH3(CH2)3CH(CH2CH3)CH2(CH2)2CH3
5. 3-octanol:
Identify the longest carbon chain, which is 8 carbons (octanol). The OH group indicates an alcohol functional group attached to position 3:
CH3(CH2)4CH(OH)CH2CH3
6. 2-methyl-2-pentene:
Find the longest carbon chain, which is 5 carbons (pentene). Add the methyl group at position 2:
CH3CH=C(CH3)CH2CH3
7. 5-methyl-1-hexene:
Identify the longest carbon chain, which is 6 carbons (hexene). Add the methyl group at position 5:
CH3CH2CH=CH(CH3)CH2CH3
8. 2,2,4,5-tetramethylhexane:
Find the longest carbon chain, which is 6 carbons (hexane). Add the four methyl groups at positions 2, 2, 4, and 5:
(CH3)4C(CH2)2CH3
9. propanoic acid:
Propanoic acid has a carboxylic acid functional group (COOH) attached to a 3-carbon chain:
CH3CH2COOH
10. 2-pentyne:
Identify the longest carbon chain, which is 5 carbons (pentyne). Place the triple bond between the second and third carbon atom:
CH3C≡CCH2CH3
Remember, practice makes perfect when it comes to writing condensed structural formulas.