posted by Anonymous .
The statement 'The median of a distribution is approximately equal to the
mean of the distribution' can be made true by adding which of the
a. For all distributions
b. only for symmetric, mound-shaped distributions
c. For skewed distributions
d. For symmetric distributions
e. None of these
I am stuck between b and d. I am for certain that when mean is equal to
median the distribution is symmetric. If I had to guess, I would choose b.
I would choose b. For any symmetric distribution, the mean will be at the axis of symmetry of the distribution, and so will the median. The distribution does not have to be "mound shaped".