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Thank you!!

A survey of an urban university (population of 25,450) showed that 750 of 1100 students sampled attended a home football game during the season. What inferences can be made about student attendance at football games?

Using the 99% level of confidence, what is the confidence interval?

a. [0.767, 0.814]

b. [0.0.6550, 0.7050]

c. [0.6659, 0.6941]

d. [0.0.6795, 0.6805]

  • Statistics -

    I believe the answer is 'none of the above'

    The formula for the confidence interval is:
    P +or- Z(99) * sqrt(P*Q/n)

    P is the estimated probability of attendence = 750/1100 = .6818
    Q = 1-P
    n = sample size = 1100
    Z(99) is the number of standard deviations away from the mean that 99% of the population fall = 2.575

    So Z(99)*sqrt(P*Q/n) = .03616.
    So the range should be (.6456, .7180)

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