question: given that y is inversely proportional to (x-1),
A) express y in terms of x and a constant k
b) give that y=5 when x=3, find x when y=25
answer: A)y=-k(x-1)
y=-kx+k
B)y=5, x=3, k(constant)=3x5
k=15
25=-15x+15
10=-15x
x=-10/15
is this correct? i'm not too sure about this variation thing, i would appreciate your help!
Your expression for y is incorrect, try this instead...
A) y is inversely proportional to (x-1) if there exists a non-zero constant k such that y = k/(x-1).
B) Given that when y=5 x=3, we can solve for k in y = k/(x-1) as follows:
5 = k/(3-1)
5 = k/2
5(2) = k [cross multiply]
10 = k or k=10
Check the result: Substitute k=10 when y=5 and x=3:
y = k/(x-1)
5 = 10/(3-1)
5 = 10/2
5 = 5 is true, therefore k=10 is correct
Now, substituting k=10, find x when y =25:
y = k/(x-1)
25 = 10/(x-1)
25(x-1) = 10 [cross multiply]
25x - 25 = 10
25x - 25 + 25 = 10 + 25
25x = 35
x = 35/25 or x=7/5
Check the result: Substitute x=7/5 when y=25 and k=10:
y = k/(x-1)
25 = 10/((7/5) - 1)
25((7/5) - 1) = 10 [cross multiply
25 ((7/5) - (5/5)) = 10
25 (2/5) = 10
25(2)/5 = 10
50/5 = 10
10 = 10 is true, therefore x=7/5 is correct