# Math - Logarithmic

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Solve:
2^(5x-6) = 7

My work:
log^(5x-6) = log7
5x - 6(log2) = log7
5x = log7 + 6(log2)
x = (log7 + log2^6) / 5

(log7) / (log2)

What did I do wrong?

• Math - Logarithmic -

you are wrong and the textbook answer, the way you stated is, is wrong.

2^(5x-6) = 7
log[2^(5x-6)] = log7
(5x-6)log2 = log7
5x-6 = log7/log2
5x = log7/log2 + 6
x = (log7/log2 + 6)/5

• Math - Logarithmic -

Without using a calculator, find the value of the following logarithmic expression.

log7 1

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