Math - Logarithmic

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Solve:
2^(5x-6) = 7


My work:
log^(5x-6) = log7
5x - 6(log2) = log7
5x = log7 + 6(log2)
x = (log7 + log2^6) / 5


And textbook answer:
(log7) / (log2)


What did I do wrong?

  • Math - Logarithmic -

    you are wrong and the textbook answer, the way you stated is, is wrong.

    2^(5x-6) = 7
    log[2^(5x-6)] = log7
    (5x-6)log2 = log7
    5x-6 = log7/log2
    5x = log7/log2 + 6
    x = (log7/log2 + 6)/5

  • Math - Logarithmic -

    Without using a calculator, find the value of the following logarithmic expression.

    log7 1

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