Manganese dioxide reacts with bromide ions to form manganese ions and bromate ions in an acidic aqueous solution. Write the balanced equation for this reaction.
1)Br- + MnO2 + 3H2O --> Mn2+ + BrO3- + 2H3O+
2)Br- + 3MnO2 + 6H3O+ ---> 3Mn2+ + 9H2O + BrO3-
3)6Br- + MnO2 + 48H2O ---> Mn2+ + 32H3O+ + 6BrO3-
4)4Br- + 3MnO2 + 18H2O ---> 3Mn2+ + 12H3O+ + 4BrO3-
5)Br- + 3MnO2 + 3H3O+ ---> 3Mn2+ + BrO3- + 3H2O
I got the first one. Is that right?
1)Br- + MnO2 + 3H2O Mn2+ + BrO3- + 2H3O+
2)Br- + 3MnO2 + 6H3O+ 3Mn2+ + 9H2O + BrO3-
3)6Br- + MnO2 + 48H2O Mn2+ + 32H3O+ + 6BrO3-
4)4Br- + 3MnO2 + 18H2O 3Mn2+ + 12H3O+ + 4BrO3-
5)Br- + 3MnO2 + 3H3O+ 3Mn2+ + BrO3- + 3H2O
I got the first one. Is that right?
Your equatioh isn' balanced. Furthermore, several students (you are one of them) don't use arrows. How can you tell which are reactants and which are products with no arrow?
(Charge doesn' balance. On left you have 1- and 2+ = 1+. On the right you have 2+, 1-, 2+ = 3+.
To determine the correct balanced equation for the reaction between manganese dioxide and bromide ions in an acidic aqueous solution, we need to ensure that the number of atoms of each element is balanced on both sides of the chemical equation.
Let's break down the reaction and balance it step by step:
1. The reaction involves manganese dioxide (MnO2) and bromide ions (Br-) in an acidic solution.
2. The reactants are manganese dioxide (MnO2) and bromide ions (Br-).
3. The products formed are manganese ions (Mn2+) and bromate ions (BrO3-) in addition to water (H2O) and hydronium ions (H3O+).
4. Start by balancing the bromine (Br) atoms. On the reactant side, we have one bromine atom on the left (Br-), while on the product side, we have one bromine atom in the bromate ion (BrO3-).
5. Next, balance the manganese (Mn) atoms. We have one manganese atom on the reactant side (MnO2), so we need one on the product side (Mn2+).
6. Now, let's balance the oxygen (O) atoms. On the reactant side, we have two oxygen atoms in manganese dioxide (MnO2). The product side has three oxygen atoms in the bromate ion (BrO3-) and one in water (H2O). This totals to four oxygen atoms.
7. To balance the oxygen atoms, we add three water molecules (H2O) on the reactant side.
8. Finally, balance the hydrogen (H) atoms. On the reactant side, we have zero hydrogen atoms, while on the product side, we have six hydrogen atoms in the hydronium ions (H3O+) and three hydrogen atoms in water (H2O). This totals to nine hydrogen atoms.
9. To balance the hydrogen atoms, we add six hydronium ions (H3O+) on the reactant side.
Following these steps, we can conclude that the balanced equation for the reaction is:
Br- + 3MnO2 + 3H3O+ → 3Mn2+ + BrO3- + 3H2O
So, the correct answer is option 5:
Br- + 3MnO2 + 3H3O+ → 3Mn2+ + BrO3- + 3H2O