# MATH

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1.The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times the length of the base. If the perimeter is 29 cm, find the length of one of the equal legs.

A)
4 cm

B)
5 cm

C)
11 cm

D)
12 cm
4x-8= 4(5)-8= 20-8= 12
2.3x - 2y = 6
X=4 and Y=3

3*4=12
x = 2/3y + 2
3.solve. -3(x+1)=2(x-8)+3
X=2

• MATH -

I call the base b
then each leg is (4b-8)
then the perimeter is 2(4b-8)+b
so
2(4b-8)+b = 29

in the end you should get base b = 5 and the two equal legs are each 12

• MATH -

let the base be x
then each of the other sides is 4x-8

4x+8 + 4x+8 + x = 29
.
.
x=5
2x-8=12
then the triangle has base 5 and the other two sides are 12 each, it checks out

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