MATH
posted by mary .
1.The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times the length of the base. If the perimeter is 29 cm, find the length of one of the equal legs.
A)
4 cm
B)
5 cm
C)
11 cm
D)
12 cm
answers
4x8= 4(5)8= 208= 12
2.3x  2y = 6
answer
X=4 and Y=3
3*4=12
x = 2/3y + 2
3.solve. 3(x+1)=2(x8)+3
ANSWER
X=2

I call the base b
then each leg is (4b8)
then the perimeter is 2(4b8)+b
so
2(4b8)+b = 29
in the end you should get base b = 5 and the two equal legs are each 12 
let the base be x
then each of the other sides is 4x8
4x+8 + 4x+8 + x = 29
.
.
x=5
2x8=12
then the triangle has base 5 and the other two sides are 12 each, it checks out
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