posted by mary .
1.The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times the length of the base. If the perimeter is 29 cm, find the length of one of the equal legs.
4x-8= 4(5)-8= 20-8= 12
2.3x - 2y = 6
X=4 and Y=3
x = 2/3y + 2
I call the base b
then each leg is (4b-8)
then the perimeter is 2(4b-8)+b
2(4b-8)+b = 29
in the end you should get base b = 5 and the two equal legs are each 12
let the base be x
then each of the other sides is 4x-8
4x+8 + 4x+8 + x = 29
then the triangle has base 5 and the other two sides are 12 each, it checks out