Physics

posted by .

A 5.70 kg block located on a horizontal floor is pulled by a cord that exerts a force F = 10.4 N at an angle theta = 27.5° above the horizontal. The coefficient of kinetic friction between the block and the floor is 0.10. What is the speed of the block 6.1 s after it starts moving?

I don't know how to do these equations in which they want you to find speed. A little help would be much appreciated.

  • Physics -

    This is a lot like your previous problem.

    There is a force 10.4 cos 27.5 or 9.22 N horizontal from the cord.

    There is a force 10.4 sin 27.5 or 4.80 N up from the cord

    The force the block exerts down on the floor is the weight - the pull up from the cord
    m g - 4.80 N
    = 5.70(9.8) - 4.8 = 51.06 N normal to floor

    So the friction force = .1 (51.06) = 5.11 N friction force
    the net horizontal force on the block is therefore
    9.22 - 5.11 = 4.11 N
    now do F = m a
    4.11 = 5.70 a
    a = .721 m/s^2
    initial speed o is 0 we assume
    v = 0 + a t = .721 (6.1)= 4.4 m/s

  • Physics -

    Ohh ok great I understand.
    Thanks a lot. :)

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. physics

    A 3.26 kg block located on a horizontal floor is pulled by a cord that exerts a force F = 10.4 N at an angle theta = 29.0° above the horizontal. The coefficient of kinetic friction between the block and the floor is 0.10. What is …
  2. physics

    A 3.26 kg block located on a horizontal floor is pulled by a cord that exerts a force F = 10.4 N at an angle theta = 29.0° above the horizontal. The coefficient of kinetic friction between the block and the floor is 0.10. What is …
  3. physics

    A 4.5 kg block located on a horizontal frictionless floor is pulled by a cord that exerts a force F=13.50 N at an angle theta=30.0 degrees above the horizontal. What is the speed of the block 5.50 seconds after it starts moving?
  4. physics

    A 3.24 kg block located on a horizontal frictionless floor is pulled by a cord that exerts a force F=11.8N at an angle theta=23.0degrees above the horizontal, as shown. What is the magnitude of the acceleration of the block when the …
  5. physics

    A 3.24 kg block located on a horizontal frictionless floor is pulled by a cord that exerts a force F=11.8N at an angle theta=23.0degrees above the horizontal, as shown. What is the magnitude of the acceleration of the block when the …
  6. physics

    I am trying to study for my exam i have tomorrow and this type of problem keeps giving me trouble can someone please help me:: A 3.24 kg block located on a horizontal frictionless floor is pulled by a cord that exerts a force F=11.8N …
  7. physics

    A 5.56 kg block located on a horizontal floor is pulled by a cord that exerts a force F = 10.7 N at an angle theta = 17.0° above the horizontal, as shown in the Figure. The coefficient of kinetic friction between the block and the …
  8. Physics

    A 4.58 kg block located on a horizontal floor is pulled by a cord that exerts a force F = 10.5 N at an angle theta = 25.5° above the horizontal. The coefficient of kinetic friction between the block and the floor is 0.09. What distance …
  9. physics

    A 3.90 kg block located on a horizontal frictionless floor is pulled by a cord that exerts a force F=14.1N at an angle theta=32.5degrees above the horizontal, as shown. a.) What is the magnitude of the acceleration of the block when …
  10. Physics

    A 4.96 kg block located on a horizontal frictionless floor is pulled by a cord that exerts a force F=13.7N at an angle theta=16.0degrees above the horizontal. What is the magnitude of the acceleration of the block when the force is …

More Similar Questions