A football is kicked at 15 m/s with an angle of 35 degrees with the ground.
How long is it in the air?
How far will it land?
Can someone help plz... Thanks!
To calculate the time the football is in the air, you can use the vertical component of the initial velocity. The equation to determine the time of flight for a projectile is given by:
t = (2 * v * sinθ) / g
Where:
t is the time of flight
v is the initial velocity (15 m/s in this case)
θ is the angle with the ground (35 degrees in this case)
g is the acceleration due to gravity (approximately 9.8 m/s²)
Now, let's plug in the values and calculate the time of flight:
t = (2 * 15 * sin(35)) / 9.8
t ≈ 1.95 seconds
Therefore, the football is in the air for approximately 1.95 seconds.
To calculate the horizontal distance the football will cover, you can use the horizontal component of the initial velocity, multiplied by the time of flight:
d = v * cosθ * t
Where:
d is the horizontal distance
v is the initial velocity (15 m/s in this case)
θ is the angle with the ground (35 degrees in this case)
t is the time of flight (1.95 seconds in this case)
Now, let's calculate the horizontal distance:
d = 15 * cos(35) * 1.95
d ≈ 25.07 meters
Therefore, the football will land at a distance of approximately 25.07 meters.