The density of gold is 19.3 x 10^3 kg/m^3. What buoyant force does a .6 kg gold crown experience when it is immersed in water?
B=m_water*g
=p_water*v_water*g
=p_water*v_gold*g
and to find v_gold =m/density
and from there would p_water =1000kg/m^3?
i don’t know nigh
To find the buoyant force experienced by the gold crown, we need to calculate the volume of the gold crown first.
The volume (v_gold) of the gold crown can be calculated using the formula:
v_gold = m / density
Substituting the values you provided, where m = 0.6 kg and density = 19.3 x 10^3 kg/m^3:
v_gold = 0.6 kg / (19.3 x 10^3 kg/m^3) ≈ 0.03106 x 10^-3 m^3
Now, to find the buoyant force, we need to know the density of water. The density of water (p_water) is approximately 1000 kg/m^3.
The buoyant force (B) experienced by the gold crown can be calculated using the formula:
B = p_water * v_gold * g
where g is the acceleration due to gravity (approximately 9.8 m/s^2).
Substituting the values, we have:
B = (1000 kg/m^3) * (0.03106 x 10^-3 m^3) * 9.8 m/s^2 ≈ 3.03 x 10^-1 N
Therefore, the gold crown experiences a buoyant force of approximately 0.303 N when immersed in water.