Last one, The sum of two numbers is 48. Four times the smaller number is equal to twice
the larger number. Find the two numbers.
ANS: 16, 32
Can someone please explain to me how you get this answer?
S+L=48
4S=2L or L= 2S
Can you take it from here?
To find the two numbers, let's assume the smaller number as 'x' and the larger number as 'y'.
From the given information, we know that the sum of the two numbers is 48. This can be written as:
x + y = 48 (Equation 1)
We're also given that four times the smaller number is equal to twice the larger number. Mathematically, we can express this as:
4x = 2y
Simplifying this equation, we get:
2x = y (Equation 2)
Now we have a system of two equations with two variables (Equation 1 and Equation 2).
We can solve this system by substitution or elimination.
Let's use substitution method:
From Equation 2, we can express y in terms of x as:
y = 2x
Now we substitute this value of y in Equation 1:
x + (2x) = 48
3x = 48
Dividing both sides by 3:
x = 16
Now substitute this value of x back into Equation 2 to find y:
y = 2x
y = 2(16)
y = 32
Therefore, the two numbers are 16 and 32.