For a lab, I have to write out the balanced equation for the titration of vinegar (containing acetic acid) with sodium hydroxide. But I am unsure of how to split up vinegar...
CH3COOH + NaOH --> ?
I need help writing out the products...
Lucy
Remember this. Acid + base = salt + water.
The H that makes the acetic acid and acid is the last one you wrote in the formula, which I put in bold. The OH from the NaOH then reacts with that to form HOH (H2O--water) and the salt that is left is CH3COONa.
CH3COOH + HONa --> HOH + CH3COONa
Sure, Lucy! I can help you with that.
To write the balanced equation for the titration of vinegar (acetic acid) with sodium hydroxide, we need to know the chemical formula for acetic acid.
The chemical formula for acetic acid is CH3COOH.
Now, let's break down the reaction step by step:
1. Vinegar (acetic acid, CH3COOH) reacts with sodium hydroxide (NaOH).
2. The hydrogen ion (H+) from acetic acid reacts with the hydroxide ion (OH-) from sodium hydroxide to form water (H2O).
So, the first part of the balanced equation is:
CH3COOH + NaOH --> H2O +
Now, we need to determine the remaining products. Since sodium replaces hydrogen in the reaction, sodium acetate (NaCH3COO) is formed. The balanced equation is:
CH3COOH + NaOH --> H2O + NaCH3COO
This equation represents the stoichiometry of the reaction, showing the balanced ratio of reactants and products. Keep in mind that the equation should be balanced in terms of both atoms and charge, ensuring there are an equal number of each atom on both sides of the equation.
I hope this helps! Let me know if you have any other questions.