posted by Shawna .
Find the exact values of the six trigonometric functions of theta if the terminal side of theta in standard position contains the point (-5/-4)
well, the points give you the opposite side, and the adjacent side. The hypotenuse must then be sqrt (25+16). So now one knows all three sides.
Use the formulas for sine, cosine, and tangent, then invert them for the other three.
so R would be sqrt41 and then sin=-4/sqrt41 cos=-5/sqrt41 and so on and so forth right?
The values of the six trig. functions should be:
sin(theta) = -4
cos(theta) = -5
tang(theta) = 4/5
csc(theta = sqrt(41)
sec(theta) = sqrt(41)