4NH3 + 7O2 --> 4NO2 + 6H20
1) How many grams of oxygen are necessary to produce 4.50 moles of NO2?
2) How many molecules of water are produced when 2.25 moles of ammonia are completely reacted?
1.Convert 4.5 mol NO2 to mols oxygen using the coefficients in the balanced equation.
Convert mols oxygen to grams oxygen. grams oxygen = mols oxygen x molar mass oxygen.
2. Convert 2.25 mols NH3 to mols H2O using the coefficients of the equation.
Convert mols H2O to molecules H2O remembering that 1 mol contains 6.02 x 10^23 molecules.
To answer these questions, we will need to use the balanced chemical equation and calculate the molar ratios.
First, let's calculate the molar mass of NO2. Nitrogen (N) has a molar mass of 14.01 g/mol, and oxygen (O) has a molar mass of 16.00 g/mol. Adding them together, we get:
Molar mass of NO2 = 14.01 g/mol + (2 × 16.00 g/mol) = 46.01 g/mol
Now, let's address each question:
1) How many grams of oxygen are necessary to produce 4.50 moles of NO2?
According to the balanced chemical equation, the molar ratio between O2 and NO2 is 7:4. This means that for every 7 moles of O2, we produce 4 moles of NO2. To calculate the grams of O2 needed, we can use the molar mass of O2, which is 32.00 g/mol.
First, we need to calculate the moles of O2 corresponding to 4.50 moles of NO2.
Moles of O2 = (4.50 moles NO2) × (7 moles O2 / 4 moles NO2) = 7.875 moles O2
Now, we can calculate the grams of O2 needed:
Grams of O2 = (7.875 moles O2) × (32.00 g/mol) = 252 grams of O2
Therefore, 252 grams of oxygen are necessary to produce 4.50 moles of NO2.
2) How many molecules of water are produced when 2.25 moles of ammonia are completely reacted?
Again, referring to the balanced chemical equation, the molar ratio between NH3 and H2O is 4:6. This means that for every 4 moles of NH3, we produce 6 moles of H2O.
To calculate the number of molecules of water, we need to convert moles of NH3 to moles of H2O first:
Moles of H2O = (2.25 moles NH3) × (6 moles H2O / 4 moles NH3) = 3.375 moles H2O
Next, we need to convert moles of H2O to molecules of H2O. We know that 1 mole of any substance contains 6.022 × 10^23 particles (Avogadro's number).
Molecules of H2O = (3.375 moles H2O) × (6.022 × 10^23 molecules/mole) = 2.034 × 10^24 molecules of H2O
Therefore, 2.034 × 10^24 molecules of water are produced when 2.25 moles of ammonia are completely reacted.