What is the oxidation states for all three elements in the formula Rb2SO3 ?
Is this correct?-1,+8,-2
+1,+4,-2 is the oxidation numbers for Rb2SO4 in order that the elements are shown in the formula.
The Oxidation number are as follows:
Rb = 1+
S = 6
O= -2
Because Rb2SO4 are a Neutral Compound therefore all the oxidation numbers should equal to 0
No. Rubidium is an alkali metal and its oxidation number is +1. Your oxidation nuber for O is correct. Now figure out what the number must be for S.
what is Rb2SO3?
like the compund name?