algebra
posted by kate .
can someone tell me if i did the problem correct (solve by completing the square) 4x^2+2x3=0
x^2+(1/2)=3/4
x^2+(1/2)+(1/4)^2=3/4+(1/4)^2
(x+1/4)^2=13/16
x+1/4=+sqrt 13/16
x+1/4=+sqrt 13/4
x=1/4+sqrt 13/4
x=1+sqrt 13/4

algebra 
Reiny
x^2+(1/2)=3/4 should say
x^2+(1/2x)=3/4 also in the line that follows that you left out the x in the second term
to avoid problems with order of operation, write your final answer this way
x=(1+sqrt 13)/4 the way you have it only the square root term would be divided by 4
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