Algebra
posted by Annie .
For x such that 0<x<ƒÎ/2, the expression
ã(1cos^2 x)/sinx + ã(1sin^2 x)/cosx
is equivalent to:
0, 1, 2, tanx or sin2x
Any help would be appreciated. Thanks.

I assume the symbol ã is supposed to come out as √ ?
(here is how I get √
while holding down the Alt key, press 251 on the numberpad, then release the Alt key)
√(1cos^2 x)/sinx + √(1sin^2 x)/cosx
√(sin^2x)/sinx + √(cos^2x)/cosx
= sinx/sinx + cosx/cosx
= 1+1
= 2
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