Algebra

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For x such that 0<x<ƒÎ/2, the expression
ã(1-cos^2 x)/sinx + ã(1-sin^2 x)/cosx
is equivalent to:

0, 1, 2, -tanx or sin2x

Any help would be appreciated. Thanks.

  • Algebra -

    I assume the symbol ã is supposed to come out as √ ?
    (here is how I get √
    while holding down the Alt key, press 251 on the numberpad, then release the Alt key)

    √(1-cos^2 x)/sinx + √(1-sin^2 x)/cosx
    √(sin^2x)/sinx + √(cos^2x)/cosx
    = sinx/sinx + cosx/cosx
    = 1+1
    = 2

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