posted by mark .
ahhh im confused!!
Calculate the pH of a solution formed by mixing 372 mL of a solution containing 4.4 x 10-6 M NaOH with 286 mL of 6.0 x 10-2 M NaOH. Report your answer to 2 decimal places.
Are both of these NaOH? If so, calculate mols of 1, mols of the other, add mols, and divide mols/L(total volume) = molarity.
Then pOH = -log (OH^-)
and pH + pOH = 14.