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Write the electron configuration of Sn and Sn2+

Give the electron configuration of Cu+ and Cu2+

  • Lauren -

    Same response as before. If you still have a question, explain what it is that you don't undrestand.

  • Lauren -

    What I don't understand is where I get the number of dots from and what is the electron configuration

  • Lauren -

    You get the number of dots from the periodic table. For example, Na is Na. and Ba is Ba: (because Na is in group I and has 1 electrons in its outside shell and Ba is in group II and has 2 electrons in its outside shell). Cl is in group VII (or 17 depending upon which system you are using) and has 7 electrons in its outside shell.
    The electron configuration is done following two rules.
    2 s electrons, 6 p electrons, 10 d electrons, and 14 f electrons. The ORDER of filling is
    1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 which will get you through element 38. There are two exceptions in this chain; one is Cr and the other is Cu. The ground state of both Cr and Cu have 1 fewer electron in the 4s and 1 more electron in the 3d than the above scheme provides. Let me know if you still have questions about this but please be specific.

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