Solve log(1/8) x=-1
Can some explain how to do this along with the answer.
I assume you meant
log (x/8)=-1
Take antilog of each side...
x/8=1/10
solve for x.
no i put it exactly how the paper has it log^1/8) and then it has x=-1 I do not understand how to do it at all.
To solve the equation log(1/8) x = -1, we need to apply the rules of logarithms. The equation can be rewritten as:
x = 10^(-1) / (1/8)
First, we simplify the expression 10^(-1) as 1/10:
x = 1/10 / (1/8)
To divide two fractions, we multiply the first fraction by the reciprocal of the second fraction:
x = 1/10 * (8/1)
Multiplying across:
x = 8/10
The fraction 8/10 can be simplified by dividing both the numerator and denominator by their greatest common divisor, which is 2. So:
x = 4/5
Hence, the solution to the equation log(1/8) x = -1 is x = 4/5.