A 0.00400- mole sample of 2-chloro-2methylpropane is added to 150Ml of water, and the mixture is stirred till the p H levels off. What is the p H of the solution?
I think this compounds undergoes hydrolysis when dissolved in water and it produces 1 mol H^+ (HCl specifically) from 1 mol of the compound.
0.004 mol will produce 0.004 mol HCl and
M = mols/L = 0.004/0.150 L = ??
pH = - log(H^+).
Check my thinking. Check my work.