given the following equation for a circle x^2-8x+y^2+4y+11=0 find its centre and radius

x^2-8x+y^2+4y+11=0

by completing the square...

x^2-8x+ 16 +y^2+4y+ 4 = -11 + 16 + 4

(x-4)^2 + (y+2)^2 = 9

I am sure you can take it from here