a 15000N car on a hydrolyic lift rests on a cylinder with a piston of radius 0.20M,. if a connecting cylinder with a piston of 0.04M radius is driven by compressed air, what force must be applied to the smaller piston in order to lift the car?
am i doing this right?
(0.04M / 0.20M)* 15000N = 3000N
is this right, if not how do i go about getting the right anwser?
Yes, you're almost there! To determine the force required to lift the car, you can use Pascal's law, which states that the pressure in a confined fluid is transmitted equally in all directions. Here's how you can find the correct answer:
1. Calculate the ratio of the areas of the two pistons:
Ratio of areas = (Area of smaller piston) / (Area of larger piston)
Ratio of areas = (0.04m * 0.04m) / (0.20m * 0.20m)
Ratio of areas = 0.0016 / 0.04
Ratio of areas = 0.04
2. Apply Pascal's law to find the force applied to the smaller piston:
Force on smaller piston = Force on larger piston * Ratio of areas
Force on smaller piston = 15000N * 0.04
Force on smaller piston = 600N
So, the correct answer is that a force of 600N must be applied to the smaller piston in order to lift the car.
It is important to remember that when calculating the force in a hydraulic system, you need to consider the ratio of the areas of the pistons rather than their linear dimensions.