A bricklayer's assistant starts building a wall, laying 50 bricks per hour. Two hours later the master comes and lays down 80 bricks per hour.
x= number of hours since the assistant has been laying.
Qusestion--------
Write expressions for the number of bricks the assistant has laid and the number of bricks tha the master has laid.
Please help me.
I understand this stuff, but this problem is just stumpiing me!!!
<<Write expressions for the number of bricks the assistant has laid and the number of bricks that the master has laid.>>
Assistant: N1 = 50 x
Master: N2 = 80 (x-2) (x>2)
in terms of x how many bricks has rick laid ??
To write expressions for the number of bricks the assistant and the master have laid, we first need to determine the number of hours each of them has been working.
Given:
The assistant starts building the wall and lays 50 bricks per hour.
Two hours later, the master joins and lays 80 bricks per hour.
Let's assign 'x' to represent the number of hours the assistant has been laying bricks.
Since the assistant starts building the wall, the number of hours he has been working is 'x' hours.
Therefore, the number of bricks the assistant has laid is given by:
Assistant's bricks = Number of hours * Number of bricks laid per hour
Assistant's bricks = x * 50
Now, let's find the number of hours the master has been working.
Since the assistant starts two hours before the master, the number of hours the master has been working is 'x - 2' hours.
Therefore, the number of bricks the master has laid is given by:
Master's bricks = Number of hours * Number of bricks laid per hour
Master's bricks = (x - 2) * 80
So, the expressions for the number of bricks laid by the assistant and the master are:
Assistant's bricks = 50x
Master's bricks = 80(x - 2)
Now you can substitute any value of 'x' to find the specific number of bricks laid by either the assistant or the master.