A distance of 1 meter separates two negative electric charges of 1-coulomb each.
With what force (in Newtons) do they repel each other. The coulomb constant is
9x10^9 Nm^2/C^2
would this be 1 N???
No, the answer is not 1 N. Look up and apply Coulomb's law.
Force = k Q1 Q2/R^2
The k is the Coulombs constant. The rest of the terms in the equaation are 1 in SI units in your case. This results in a very large value for the force, in Newtons
To calculate the force between two electric charges, you can use Coulomb's law, which states that the force (F) between two charges (q1 and q2) is given by the formula:
F = (k * |q1 * q2|) / r^2
where:
- F is the force between the charges
- k is the Coulomb constant (9x10^9 Nm^2/C^2)
- q1 and q2 are the magnitudes of the charges
- r is the distance between the charges
In your case, you have two negative charges of 1-coulomb each (q1 = -1 C and q2 = -1 C) separated by a distance of 1 meter (r = 1 m). Substituting these values into Coulomb's law:
F = (9x10^9 Nm^2/C^2 * |-1 C * -1 C|) / (1 m)^2
= (9x10^9 Nm^2/C^2 * 1 C^2) / 1 m^2
= 9x10^9 N
Therefore, the force of repulsion between the two charges is 9x10^9 Newtons.