Physics
posted by Lindsay .
A regulation volleyball court is L = 18.0 m long and a regulation volleyball net is d = 2.43 m high. A volleyball player strikes the ball a height h = 1.76 m directly above the back line, and the ball's initial velocity makes an angle q = 55° with respect to the ground. At what initial speed must the ball be hit so that it just barely makes it over the net? (Assume the volleyball is hit so that its path is parallel to the sideline as seen from an observer directly above the court, and that the volleyball is a point object.)
Again, I need some of the first steps. I can probably get it after that.

You will also need to neglect air fraction to get an easy answer.
Solve for the value of V that puts the ball at the height of the net after traveling 9.0 m. (Nine meters is the half court length). You want the value of V that results in the ball being 0.67 m above the elevation where it was struck, at time T.
Vsin 55*T  (g/2)T^2 = 0.67
Vcos 55*T = 9.0
Two variables, two unknowns. 
Now it asks for the max. height. above the court reached by the ball. Do I use the equation Vf^2 = vi^2 + 2(g)(delta y) ?

Start with the height that the ball was hit, and add an amount y such that
g y = (1/2) (Vsin 55)^2
since the ball took off at 55 degrees to horizontal.
The ball should have risen to a height higher then the net, and then passed just over it coming down 
Ok so I have the initial speed and the max height. Now it asks "At what initial speed must the ball be hit so that it lands directly on the opponent's back line?"
Do I use a process similar to that of the first question? 
yes, same process

Would my equation for the xdir. be Vcos 55*T = 18, since it's the full length of the court?
What would my height for the ydir. be? Vsin 55*T  (g/2)T^2 = ??? 
Yes, 18 m would be the length to use. The height (y change) would be MINUS the elevation where the ball was struck, since that would correspond to hitting the ground
Respond to this Question
Similar Questions

Physics repost
A regulation volleyball court is L = 18.0 m long and a regulation volleyball net is d = 2.43 m high. A volleyball player strikes the ball a height h = 1.76 m directly above the back line, and the ball's initial velocity makes an angle … 
Physics
A regulation volleyball court is L = 18.0 m long and a regulation volleyball net is d = 2.43 m high. A volleyball player strikes the ball a height h = 1.76 m directly above the back line, and the ball's initial velocity makes an angle … 
Physics
A regulation volleyball court is L = 18.0 m long and a regulation volleyball net is d = 2.43 m high. A volleyball player strikes the ball a height h = 1.76 m directly above the back line, and the ball's initial velocity makes an angle … 
Math
A volleyball is his upward by a player in a game. The height h (in fee) of the volleyball after t seconds is given by the function h=16t^2+30t+6. What is the maximum height of the volleyball? 
Physics
Stephanie serves a volleyball from a height of 0.78 m and gives it an initial velocity of +7.7 m/s straight up. How high will the volleyball go? 
Physics
Stephanie hits a volleyball from a height of 0.80m and gives it on initial velocity of 17.5m/s straight up 1. How high will the volleyball go? 
Physics
A volleyball is launched straight up at an initial velocity of 2.3 m/s. It is then spiked by a taller player 0.8 meters above the launch height. How high did it rise, and how long did the volleyball remain in the air between the players? 
Physics
A volleyball court is 18 m long from baseline to baseline and the net is 2.24 m high. A volleyball player serves the ball from the baseline by hitting it at a height of 2 m above the floor at an angle of 10 degrees above the horizontal. … 
Physics
Veronica hits a volleyball from a height of 0.4 m and gives it an initial velocity of 5.2 m/s straight up. a) How high, above the ground, will the volleyball go b) How long will it take the ball to reach its maximum height? 
Quadratic Relations, Algebra, Math
URGENT!! PLEASE HELP In a volleyball match. Jenny serves the volleyball at 14m/s, from a height of 2.5m above the court. The height o the ball in flight can be estimated using the equation h=4.9t^2+14t+2.5, where h is the height, …