A rectangle's length is 8 cm more than three times it's width. If the perimeter is 128 cm, find the length and width. What is the equation for this?

L + L + W + W = 128

L - 8 = 3W
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Two equations. Two unknowns. Solve simultaneously.

3 and 8

To find the equation for this problem, we can break it down into two steps:

Step 1: Define the variables.
Let's assign variables to the length and width of the rectangle. We'll use "L" for length and "W" for width.

Step 2: Set up the equations.
From the problem statement, we know that the length is 8 cm more than three times the width. Therefore, we can write the equation for the length as:
L = 3W + 8

The perimeter of a rectangle can be calculated by using the formula:
Perimeter = 2(L + W)

In this case, the perimeter is given as 128 cm, so we can write the equation for the perimeter as:
128 = 2(L + W)

Now, we have two equations:
L = 3W + 8
128 = 2(L + W)

These equations can be used to solve for the length and width of the rectangle.

You need to sove two simultaneous equations.

L = length W = width

L = 3W + 8
2(L + W) = 128

Substitute 3W +8 for L in the last equation.
2[(3W+8)+ 2W] = 128
8W + 16 = 128
8W = 112
W = ?
L = 3W +8 = ?