physics
posted by ken .
A ball is attached to a string with length of L. It swings in a horizontal circle, with a constant speed. The string makes an angle (theta) with the vertical, and T is the magnitude of the tension in the string.
1)Determine the Mass of the Ball.
2)Determine th Speed of the Ball.
3)Determine the Frequency of revolutions of the Ball.
1)
F=Tsin(theta)=ma
m= (Tcos theta)/g
Tcos(theta) mg= 0
T= mg/[cos(theta)]
F=Tsin(theta)
F= mg/[cos(theta)] * sin(theta) subtitute for T
F=mgtan(theta)
F=(mv^2)/r r=Lsin(theta)
mgtan(theta)=(mv^2)/ Lsin(theta)
v= square root of gLtan(theta)sin(theta)
3)
T= 2pi time square root of (l /g)
frequency= 1/t
frequency= 1/ [ 2pi time square root of (l /g) ]
I need comment about my solution. Thanks

physics 
drwls
(1) T cos theta = mg
m = (T/g) cos theta
(2) T sin theta = m V^2/r
= (T/g) cos theta V^2/r
tan theta = V^2/(gr)
V = sqrt [g r tan theta)
3) V * period = V/f = 2 pi r
f = [1/(2 pi)]* sqrt (g r tan theta) 
P.E 
Anonymous
tennis
scoring.
zero/nothing iz called ? 
physics 
drwls
Anonymous, you should have posted this as a new question, not under someone else's physics question
In tennis, zero is "love"
The expression "love" originated in the French word "l'ouef" (the goose egg), but in French tournaments today, the official uses the word "zero" when announcing the score. 
physics 
annon
(1) T cos theta = mg
m = (T/g) cos theta
(2) T sin theta = m V^2/r
= (T/g) cos theta V^2/r
tan theta = V^2/(gr)
V = sqrt [g r tan theta)
3) V * period = V/f = 2 pi r
f = [1/(2 pi)]* sqrt (g r tan theta)
Respond to this Question
Similar Questions

physics
Estimate the force a person must exert on a string attached to a 0.120 kg ball to make the ball revolve in a circle when the length of the string is 0.600 m. The ball makes 1.20 revolutions per second. Do not ignore the weight of the … 
Physics
Estimate the force a person must exert on a string attached to a 0.160 kg ball to make the ball revolve in a circle when the length of the string is 0.600 m. The ball makes 1.80 revolutions per second. Do not ignore the weight of the … 
physics
A stone is tied to a string (length = 1.05 m) and whirled in a circle at the same constant speed in two different ways. First, the circle is horizontal and the string is nearly parallel to the ground. Next, the circle is vertical. … 
Physics
A ball having a mass of 4 kg is attached to a string 1 m long and is whirled in a vertical circle at a constant speed of 23 m/s. (a) Determine the tension in the string when the ball is at the top of the circle. (b) Determine the tension … 
Physics
Imagine that you swing about your head a ball attached to the end of a string. The ball moves at a constant speed in a horizontal circle. Part A If the mass of the ball is 0.160kg and you supply a tension force of 14.5N to the string, … 
physics
A stone is tied to a string (length = 1.25 m) and whirled in a circle at the same constant speed in two different ways. First, the circle is horizontal and the string is nearly parallel to the ground. Next, the circle is vertical. … 
Physics
A tennis ball connected to a string is spun around in a vertical, circular path at a uniform speed. The ball has a mass m = 0.162 kg and moves at v = 4.73 m/s. The circular path has a radius of R = 0.87 m 1)What is the magnitude of … 
Physics
A tennis ball connected to a string is spun around in a vertical, circular path at a uniform speed. The ball has a mass m = 0.162 kg and moves at v = 4.73 m/s. The circular path has a radius of R = 0.87 m 1)What is the magnitude of … 
physics
A mass m = 6.0 kg is attached to the lower end of a massless string of length L = 27.0 cm. The upper end of the string is held fixed. Suppose that the mass moves in a circle at constant speed, and that the string makes an angle theta … 
physics
A mass m = 9.0 kg is attached to the lower end of a massless string of length L = 83.0 cm. The upper end of the string is held fixed. Suppose that the mass moves in a circle at constant speed, and that the string makes an angle theta …