Algebra 2(quadratic)
posted by Chels .
Use the value of the discriminant to determine the number and type of roots for the equation: (x^2+20=12x16)
1 real, irrational
2 real, rational
no real
1 real, rational

For quadratics, either both roots are real or both are complex. In a special case where the discriminant is zero, there is one root.
In your case, the equation should be written in the ax^2 + bx + c = 0 form, which would be
x^2 12x + 36 = 0.
discriminant = b^2  4ac = 144144 = 0
So there is only one root.
x = b/2a = 6, which is a rational number
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