A bullet weighing 235 grains is moving at a speed of 2.52 X 10^3 ft/s. Calculate the kinetcic energy of the bullet in joules ahd in calories. One grain equals 0.0648 g.
Can someone help me out on this please
Sure! To calculate the kinetic energy of the bullet, we can use the formula:
Kinetic Energy (K.E.) = (1/2) * mass * velocity^2
First, let's convert the weight of the bullet from grains to grams. Since 1 grain equals 0.0648 g, we can calculate the mass of the bullet as follows:
Mass = weight in grains * 0.0648 g/grain
Given that the weight of the bullet is 235 grains, we can calculate the mass as follows:
Mass = 235 grains * 0.0648 g/grain = 15.228 g
Next, we need to convert the speed of the bullet from feet/second (ft/s) to meter/second (m/s) to be able to use the formula. Since 1 meter is approximately equal to 3.281 feet, we can convert the speed as follows:
Velocity in m/s = velocity in ft/s / 3.281 ft/m
Given that the velocity of the bullet is 2.52 X 10^3 ft/s, we can calculate the velocity in m/s as follows:
Velocity in m/s = (2.52 X 10^3 ft/s) / 3.281 ft/m = 767.62 m/s
Now, we can calculate the kinetic energy of the bullet in joules using the formula mentioned above:
K.E. = (1/2) * mass * velocity^2
To substitute the values into the formula:
K.E. = (1/2) * (15.228 g) * (767.62 m/s)^2
K.E. = (1/2) * (15.228 g) * (767.62^2 m^2/s^2)
K.E. = 5846481.392 joules
Therefore, the kinetic energy of the bullet is approximately 5,846,481 joules.
To calculate the kinetic energy of the bullet in calories, we can use the conversion factor: 1 calorie = 4.184 joules.
K.E. in calories = K.E. in joules / 4.184
K.E. in calories = 5,846,481 joules / 4.184
K.E. in calories = 1,397,088.06 calories
Therefore, the kinetic energy of the bullet is approximately 1,397,088.06 calories.
I hope this helps! Let me know if you have any further questions.
K. E.= 1/2 mv2 .
Convert m to kg
Convert ft/sec to meters/second.
Then KE you obtain is in Joules. There are 4.184 J in 1 calorie.