Balance Eq.:
Na2Co3+ CaCl2--> CaCo3+ 2NaCl. (CHALK)
Calculate the mass of a dry precipitate.
Calculate the mass of moles of the precipitate produced in the reaction.
BTW, that is a capital O for Na2CO3 and CaCO3.
BTW?
BTW = by the way.
To calculate the mass of a dry precipitate, you need to know the stoichiometry of the reaction. In this case, the balanced equation is:
Na2Co3 + CaCl2 → CaCo3 + 2NaCl
According to the equation, 1 mole of calcium carbonate (CaCo3) is formed for every 1 mole of sodium carbonate (Na2Co3) and calcium chloride (CaCl2) reacted.
To find the mass of a dry precipitate, you'll need the amount (in moles) of the relevant substances reacted. From the balanced equation, you know that the ratio of Na2Co3 to CaCo3 is 1:1.
Now, let's assume you have reacted 1 mole of Na2Co3. This means you will also have 1 mole of CaCo3 as the product.
To calculate the mass of the CaCo3 precipitate, you'll need to multiply the number of moles by the molar mass of CaCo3. The molar mass of CaCo3 is the sum of the atomic masses of calcium (Ca), carbon (C), and three oxygen (O) atoms.
The atomic masses are:
Ca = 40.08 g/mol
C = 12.01 g/mol
O = 16.00 g/mol
Adding them together, you get:
molar mass of CaCo3 = (40.08 g/mol) + (12.01 g/mol) + (3 * 16.00 g/mol) = 100.09 g/mol
Since you have 1 mole of CaCo3, the mass of the dry precipitate will be:
mass of dry precipitate = 1 mole * 100.09 g/mol = 100.09 g
Therefore, the mass of the dry precipitate is 100.09 grams.
To calculate the mass of moles of the precipitate produced in the reaction, you would follow the same steps as described above. However, if you have a specific amount (in grams) of one of the reactants or products, you would need to use stoichiometry and the molar masses of the substances to convert to moles.