Post a New Question

Physics

posted by .

How do i do this ? ? ?



: Suppose you have collected the data shown below for the circuit in Figure 1.

Voltage is measured across the
resistor. Current is measured
through the resistor. The
exact value of the resistor is
100 Ω.
Figure 1.

DESCRIBE THE MEASURED QUANTITIES:

“x” Electric Current in Amperes .

“y” Voltage in Volts .

DATA:

TRIAL “x” (units) “y” (units) k = y/x
1 .041 A 4.0 V
2 .083 A 8.2 V
3 .127 A 12.3 V
4 .162 A. 16.0 V
5 .200 A 21.0 V




EQUATION OF DATA (USING FORM y = mx + b): .


ACCEPTED VALUE FOR k: .


ACCURACY: AVERAGE k – ACCEPTED k x 100% = .
ACCEPTED k


PRECISION: HIGHEST VALUE OF k x 100% = .
LOWEST VALUE OF k
.


ACCURACY: AVERAGE k – ACCEPTED k x 100% = .
ACCEPTED k


PRECISION: HIGHEST VALUE OF k x 100% = .
LOWEST VALUE OF k

  • Physics -

    TRIAL “x” (units) “y” (units) k = y/x
    1 .041 A 4.0 V
    2 .083 A 8.2 V
    3 .127 A 12.3 V
    4 .162 A. 16.0 V
    5 .200 A 21.0 V

  • Physics -

    “x”(units)“y” (units)k = y/x
    1.041 A 4.0 V
    2.083 A 8.2 V
    3.127 A 12.3 V
    4.162 A.16.0 V
    5.200 A 21.0 V

  • Physics -

    NEVER MIND I CANT Get it to post

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question