34. [(x^2 + x)/(x^2 - x)]^1/2 My answer: [(-2x^2)]/[(x^2 + x)^1/2 * (x^2-x)^3/2] The book's answer is: [(-1)] / [(x-1)^3/2 * (x + 1)^1/2]
f(x)= [(x^2 + x)/(x^2 - x)]^1/2 = [x(x+1)/x(x-1)]^1/2 = [(x+1)/(x-1)]^1/2 Derivative: df/dx = (1/2)[(x+1)/(x-1)]^-1/2* [(x-1)-(x+1)]/(x-1)^2 =[-(x-1)/(x+1)]^1/2* [(x-1)^2] = -(x-1)^-3/2 * (x+1)^-1/2
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