If a person jumped off the side of a ship from 20 feet high what speed would they be travelling at when they impact the water?
Thanks
Mike
Use the formula
V = sqrt (2 g H)
g is the acceleration of gravity (9.8 m/s^2) and H is the height (20 m)
Thank you drwls but sorry just do not know where to begin.
Mike
I failed to notice that the height was H = 20 feet, not 20 m. 20 feet = 6.10 m
"sqrt (2gH)" means "square root of 2 x 9.8 x 6.1" in this case. The answer will be in units of meters per second. To get the answer in ft/s, use g = 32.2 ft/s^2 and H = 20 ft.
Just perform the calculation indicated. If you do not know how to perform calculations of this type as indicated by a formula, then I strongly advise you to seek the help of a tutor.
The part of the formula I am particularly confused about is the symbol used between the s and the 2 above?
Thanks
Mike
If this answer is somewhere near correct I have understood the formula.
A person jumping off a ship from 20 feet above the water will impact the water at about 24.5 statute MPH?
Mike
V = sqrt (2*32.2 ft/s^2 *20 ft)
= 35.9 ft/s
multiply that by 15/22 to get miles per hour...
= 24.5 mph
Looks like you understand the formula and a lot more! Congratulations
I'm sorry if you didn't understand my sqrt (x) notation. It means the square root of x.
To calculate the speed at which a person would be traveling when they impact the water after jumping off the side of a ship from a height of 20 feet, we can use the equations of motion.
First, it is important to note that the acceleration due to gravity is approximately 32.2 feet per second squared, denoted as "g."
The equation we can use to calculate the speed at impact is:
v^2 = u^2 + 2gs
where:
- v represents the final velocity (speed at impact)
- u represents the initial velocity (which is 0 when someone jumps off the ship)
- g represents the acceleration due to gravity
- s represents the distance fallen
In this case, the initial velocity is 0, and the distance fallen is 20 feet. We can plug these values into the equation:
v^2 = 0 + 2 * 32.2 * 20
Simplifying the equation:
v = √(2 * 32.2 * 20)
Using a calculator, we find:
v ≈ 28.3 feet per second (rounded to one decimal place)
Therefore, if a person were to jump off the side of a ship from a height of 20 feet, they would be traveling at approximately 28.3 feet per second when they impact the water.