what volume of water must be added to 10ml og 6.0M NaOH to make a solution that is .30 M in NaOH
How do I solve for this
Lets see. You want to dilute it 20x, so add nineteen parts water to one part sodium hydroxide.
Isn't that 190ml water, 10 ml of NaOH?
Check that. You can check it by calculating the molarity of the resulting solution.
3.97m
To solve this problem, you need to use the formula for dilution:
C1V1 = C2V2
where
C1 = initial concentration of the solution (in this case, 6.0 M)
V1 = initial volume of the solution (in this case, 10 mL)
C2 = final concentration of the solution (in this case, 0.30 M)
V2 = final volume of the solution (which we need to find)
First, let's rearrange the formula to solve for V2:
V2 = (C1V1) / C2
Now we can plug in the values:
V2 = (6.0 M * 10 mL) / 0.30 M
Solving this equation yields V2 = 200 mL.
Therefore, you need to add 200 mL of water to 10 mL of 6.0 M NaOH in order to obtain a solution that is 0.30 M in NaOH.