math
posted by shila .
If an object is fired upward from the top of a tower at a velocity of 80 feet per second, the tower is 200 ft high, the formula is
h(t)=16t^2+80t+200, t is time h is height, how long after it is fired does the object reach the max height? It is like a quadratic equation

If an object is fired upward from the top of a tower at a velocity of 80 feet per second, the tower is 200 ft high, the formula is
h(t)=16t^2+80t+200, t is time h is height, how long after it is fired does the object reach the max height? It is like a quadratic equation
The classic equation for height reached by a body projected upward is h = Vot  gt^2/2 or Vot  16t^2 where Vo = the initial upward velocity, t = the time of flight and g = the acceleration due to gravity.
Your equation of height reached is given by h = 200 + 80t  16t^2.
The equation of motion from which you can obtain the time of flight is Vf = Vo  gt where Vf = the final velocity. Since the final final velocity is zero, we have 0 = 80  32t making t = 2.5 sec.
After 2.5 sec., it will have reached its maximum height of 200 + 80(2.5)  16(2.5)^2 = 200 + 200  100 = 300 ft. 
i don't know
Respond to this Question
Similar Questions

math
Baseball Nick throws a baseball upward with an initial velocity of 60 feet per second. What is the maximum height of the ball after Nick releases the ball? 
Algebra
THe function h(t)=16t^2+v0t+h0 describes the height in feet above the ground h(t) of an object thrown vertically from a height of h0 feet, with an initial velocity of v0 feet per second, if there is no air friction and t is the time … 
Algebra
THe function h(t)=16t^2+v0t+h0 describes the height in feet above the ground h(t) of an object thrown vertically from a height of h0 feet, with an initial velocity of v0 feet per second, if there is no air friction and t is the time … 
algebra3
An object is fired straight up from the top of a 200foot tower at a velocity of 80 feet per second. The height h(t) of the object t seconds after firing is given by h(t) = 16t2 + 80t + 200. 
College Algebre
Here is the math problem: The height of an object in free fall, or otherwise thrown into the air near the earth's surface, with initial vertical velocity v0 in feet per seconds, and from the initial height h0 in feet, at any given … 
Math
The height(h) of an object that has been dropped or thrown in the air is given by: h(t)=4.9t^2+vt+h t=time in seconds(s) v=initial velocity in meters per second (m/s) h=initial height in meters(m) A ball is thrown vertically upwardd … 
Math
The height(H) of an object that has been dropped or thrown in the air is given by: H(t)=4.9t^2+vt+h t=time in seconds(s) v=initial velocity in meters per second (m/s) h=initial height in meters(m) H=height h=initial height I didn't … 
algebra 2
So the dead line for my class is coming up. And I really need help for these questions! 2. Elaine shoots an arrow upward at a speed of 32 feet per second from a bridge that is 28 feet high. The height of the arrow is given by the function … 
Math
In physics, one learns that the height of an object thrown upward from an initial height of h0 feet with an initial velocity of v0 (in feet per second) is given by the formula h(t)=−16t^2+v0t+h0 feet where t is the amount of … 
Maths
object thrown upward from an initial height of h0 feet with an initial velocity of v0 (in feet per second) is given by the formula h(t)=−16t^2+v0t+h0 feet where t is the amount of time in seconds after the ball was thrown. Also, …