Chemistry

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An experiment called for 4.83 L of sulfur dioxide at 0 degrees C and 1.00 atm. What would be the volume of this gas at 25 degrees C and 1.00 atm?

V1= 4.83 L
V2= ?
T1= 273 K
T2= 298 K
1 atm P1 and P2

V2 = V1 * T2/T1

4.83 L * 298 K /273 K =

ANSWER: 5.27 L

Is this correct.

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    yes

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