A car with mass of 1400kg is towed with a net force of 4500N. the car starts from rest, find the speed of the car traveled after it traveled 100m.
W=FnetX distance=ma x distance
4500N=(1/2)1400kg V^2
2.5m/s=V
is this right? if not what am i doing wrong?
No.
Your equations are troubling, as it reveals you have no idea what you are doing.
Work input= KE output
Netforce*distance= 1/2 m v^2
4500*100= 1/2 *1400*v^2
Solve for v. This is about ten times what you thought.
Your approach is generally correct, but there is a mistake in your calculation.
First, let's calculate the acceleration (a) of the car using Newton's second law:
F_net = ma
4500N = 1400kg * a
a = 4500N / 1400kg
a ≈ 3.214 m/s²
Now, we can use the kinematic equation to find the final velocity (V) after the car has traveled a distance of 100m from rest:
V^2 = u^2 + 2as
Where:
u = initial velocity (0 m/s as the car starts from rest)
s = distance (100m)
a = acceleration (3.214 m/s²)
Plugging in these values:
V^2 = 0^2 + 2 * 3.214 m/s² * 100m
V^2 = 0 + 642.8 m²/s²
V ≈ √(642.8) m/s
V ≈ 25.36 m/s
So, the speed of the car after traveling 100m is approximately 25.36 m/s.
Your approach is not entirely correct. Let's go through the problem and find the correct solution step by step.
To find the final speed (V) of the car after traveling 100m, we can use the equations of motion.
Step 1: Identify the known quantities:
- Mass of the car (m) = 1400 kg
- Net force acting on the car (Fnet) = 4500 N
- Distance traveled by the car (d) = 100 m
- Initial velocity of the car (u) = 0 m/s (since the car starts from rest)
Step 2: Calculate the acceleration (a) using Newton's second law: Fnet = ma
a = Fnet / m
a = 4500 N / 1400 kg
a ≈ 3.21 m/s^2
Step 3: Use the equation of motion to calculate the final velocity (V):
V^2 = u^2 + 2ad
Substituting the values,
V^2 = (0 m/s)^2 + 2 × 3.21 m/s^2 × 100 m
V^2 = 2 × 3.21 m/s^2 × 100 m
V^2 = 642 m^2/s^2
Taking the square root of both sides to find V:
V ≈ √(642 m^2/s^2)
V ≈ 25.34 m/s
So, the correct final speed of the car after traveling 100m is approximately 25.34 m/s.